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3 years ago

What is the equation in point slope form of the line that passes though the point (-1, -3) and has a slope of 4

Mathematics

1 answer:

Marizza181 [45]3 years ago

4 0

Y-b=m(x-a)
Y+3=4(x+1)
Y=4x+4-3

Y=4x-1

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AB<br> C D<br> E<br> F +3<br> x2 -3x -18

madam [21]

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3 years ago

Read 2 more answers

Whats the parallel equation of y=1/3x-2 goes through point (0,6)

loris [4]

You know that two lines are parallel if they have the same slope, so the new line will also have slope

$m=\frac{1}{3}$

Because the equation of the given line is written in the form

$\begin{gathered} y=mx+b \\ \text{Where} \\ m\colon\text{slope of the line} \\ b\colon\text{ y-intercept} \end{gathered}$

Then, you can use point slope equation, which is

$\begin{gathered} y-y_1=m(x_{}-x_1) \\ \text{Where} \\ (x_1,y_1)\colon\text{ point through which the line passes.} \\ m\colon\text{slope of the line} \end{gathered}$

So,

$\begin{gathered} (x_1,y_1)=(0,6) \\ \text{ And you have} \\ y-y_1=m(x_{}-x_1) \\ y-6=\frac{1}{3}(x-0) \\ y-6=\frac{1}{3}x-0 \\ y-6=\frac{1}{3}x \\ \text{ Add 6 to both sides of the equation} \\ y-6+6=\frac{1}{3}x+6 \\ y=\frac{1}{3}x+6 \end{gathered}$

Therefore, the equation of the line that is parallel to y=1/3x-2 and goes through point (0,6) is

$y=\frac{1}{3}x+6$

7 0

1 year ago