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ser-zykov [4K]
3 years ago
8

What are scenarios for the ratios 2:10, 10:2, & 12:1?

Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

2:10 2/10 2 to 10 10:2 10/2 10 to 2 12:1 12/1 12 to 1

Step-by-step explanation:

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Using this distribution, find the probability
kaheart [24]

Answer:

P = 0.3

Step-by-step explanation:

Here, we are to use the probability distribution in the table to calculate the probability that a children has 4 or more shoes in his or her closet

When we say 4 or more, what we mean by this is that the teenager has 4 shoes or 5 shoes

In probability expressions, when we use the term ‘or’ we are simply talking about adding the terms involved

So what we can do here is to add the probability that the teenager has 4 shoes to the probability that the teenager has five shoes

From the table that would be; 0.1 + 0.2 = 0.3

6 0
3 years ago
9÷3,746 what's the answer? can u help?​
worty [1.4K]

Answer:

The answer is 0.00240256273

4 0
2 years ago
The answers are either: 12, 2, 8, or 10 please helppp
blsea [12.9K]

Answer: 10 I believe

Step-by-step explanation:

3 0
3 years ago
3. Bob the Builder wants to earn an annual rate of 10% on his investments,
mamaluj [8]

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

T = E + P

In this question:

Rate of 10%, so I = 0.1.

9 months, so t = \frac{9}{12} = 0.75

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

T = E + P

3000 = E + P

E = 3000 - P

Then

E = P*I*t

3000 - P = P*0.1*0.75

1.075P = 3000

P = \frac{3000}{1.075}

P = 2790.7

He should pay $2,790.7.

8 0
3 years ago
Which graph represents y=x-5?​
elena-s [515]
Can uu show the rest of the graph??????
3 0
2 years ago
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