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makkiz [27]
3 years ago
10

The width of the rectangle is 40% of its length. What is the area of the rectangle?

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer:

160in²

Step-by-step explanation:

40% = 0.4 = 4/10

The length is 20, 40% of that is (0.4)(20) = 8in

Length * width . = 20*8 = 160in²

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3 years ago
The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio
bixtya [17]

The correct option is (b) h=0.5cos(\pi/6t)+9.5.

The equations can be used to model the height as a function of time, t, in hours is h=0.5cos(\pi/6t)+9.5.

<h3>Equation of cosine function:</h3>

The following is a presentation of the cosine function's generic form;

y =  a + cos(bx - c) + d

amplitude = a

b = cycle speed

Calculation for the model height;

The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.

Obtain amplitude 'a' as

\begin{aligned}a &=\frac{\text { Maximum value }-\text { Minimum value }}{2} \\a &=\frac{10-9}{2} \\a &=\frac{1}{2} \\a &=0.5\end{aligned}

The time 'T' is calculated as-

\begin{aligned}&\mathrm{T}=\frac{2 \pi}{\mathrm{b}} \\&12=\frac{2 \pi}{\mathrm{b}} \\&\mathrm{b}=\frac{2 \pi}{12} \\&\mathrm{~b}=\frac{\pi}{6}\end{aligned}

Now, calculate 'd'

\begin{aligned}&\mathrm{d}=\frac{\text { Maximum value }+\text { Minimum value }}{2} \\&\mathrm{~d}=\frac{10+9}{2} \\&\mathrm{~d}=\frac{19}{2} \\&\mathrm{~d}=9.5\end{aligned}

Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:

h=0.5cos(\pi/6t)+9.5

To know more about the general equation of a cosine function, here

brainly.com/question/27587720

#SPJ4

The complete question is-

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.

A. h=0.5cos(\pi/12t)+9.5

B. h=0.5cos(\pi/6t)+9.5

C. h=cos(\pi/12t)+9

D. h=cos(\pi/6t)+9

7 0
2 years ago
The manufacturers of m&amp;m's claim that 20% of the milk chocolate m&amp;m candies are orange. find the mean and standard devia
lora16 [44]
T<span>he mean of a sampling distribution of a sample with proportion, p and sample size, n is given by \mu=np.

</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by \sigma= \sqrt{np(1-p)}

</span>Given that t<span>he manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. The proportion is p = 0.2

The mean of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by \mu=100(0.2)=20

</span><span>The standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by \sigma= \sqrt{100(0.2)(1-0.2)} = \sqrt{16} =4</span>

8 0
3 years ago
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