So to begin, substitute all of the variables in for their corresponding value.
X=3
Y=-5
Z=-1
2XY+6YZ^2
2(3)(-5)+6(-5)(-1^2)
-30+-30
-60
Hopefully this is what they're asking for!
Answer:
The number of pies does the baker have left is 15.
Step-by-step explanation:
Given : A baker made 20 pies. A Boy Scout troop buys one–fourth of his pies, a preschool teacher buys one–third of his pies, and a caterer buys one–sixth of his pies.
To find : How many pies does the baker have left?
Solution :
Let x be the number of pies does the baker have left.
According to question,
Number of pies buys,
One-fourth =![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
One-third =![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
One-sixth =![\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D)
i.e. ![x=20-(20\times \frac{1}{4}+20\times \frac{1}{3}+20\times \frac{1}{6})](https://tex.z-dn.net/?f=x%3D20-%2820%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%2B20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%2B20%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%29)
![x=20-(5+20\times \frac{1}{3}+10\times \frac{1}{3})](https://tex.z-dn.net/?f=x%3D20-%285%2B20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%2B10%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%29)
![x=20-(5+\frac{20+10}{3})](https://tex.z-dn.net/?f=x%3D20-%285%2B%5Cfrac%7B20%2B10%7D%7B3%7D%29)
![x=20-(5+ \frac{30}{3})](https://tex.z-dn.net/?f=x%3D20-%285%2B%20%5Cfrac%7B30%7D%7B3%7D%29)
![x=20-(5+10)](https://tex.z-dn.net/?f=x%3D20-%285%2B10%29)
![x=20-(15)](https://tex.z-dn.net/?f=x%3D20-%2815%29)
![x=5](https://tex.z-dn.net/?f=x%3D5)
The number of pies does the baker have left is 15.
9514 1404 393
Answer:
(b) 38.5
Step-by-step explanation:
The polygon is a trapezoid with bases 4 and 7 and height 7. Its area is given by the formula ...
A = (1/2)(b1 +b2)h
A = (1/2)(4 +7)(7) = 77/2
A = 38.5 . . . . square units