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nata0808 [166]
2 years ago
9

Jake wants to make a garden with a border in the corner of his yard. He has lumber in several different lengths. Which three len

gths could NOT be used to make a right triangle to fit into the corner of his yard?
Mathematics
1 answer:
zhannawk [14.2K]2 years ago
3 0

Answer:

10ft,15 ft, 12ft

Step-by-step explanation:

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The difference in age between Brita and her daughter Eva is 30 years. The sum or their ages is 118. How old is Eva?
seraphim [82]

Answer: 44 years

Step-by-step explanation:

Let Brita's age be x and the daughter's age be y , then from the first statement :

x - y = 30

From the second statement :

x + y = 118

solving the resulting linear equation , add the two equations , we have

2x = 148

x = 74

substitute 74 into equation 1 to find the value of y

74- y = 30

y = 74 - 30

y = 44

Therefore :

Eva = 44 years

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Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
2 years ago
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