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2 years ago

11

Need help ASAP !!!

e=" \sqrt{2563 \times 2563} " alt=" \sqrt{2563 \times 2563} " align="absmiddle" class="latex-formula">

2 answers:

Vesnalui [34]2 years ago

5 0

Answer:

your answer will be -,+2563

Step-by-step explanation:

schepotkina [342]2 years ago

4 0

Answer:

√{2563×2563}=√2563²=±2563

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I suck at math but what's greater 0.67 or 0.6

Vesna [10]

Answer:

0.67!

Step-by-step explanation:

0.6 is just 0.60 which is less than 0.67

6 0

2 years ago

Find the polynomial of minimum degree, with real coefficients, zeros at

drek231 [11]

Answer:

$\huge\boxed{p(x)=4x^3-20x^2+4x+300}$

Step-by-step explanation:

$\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)$

$\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300$

7 0

3 years ago

Make up a story to go with the graph. You can refer to the line segments by color or number.

9966 [12]

First, Joe started the water and it was at full force. He filled it up to 9 inches. It took him 2 minutes to get to 9 inches. Then, he stopped it for 2 minutes because his mom called him to get a bar of soap. The water level was still at 9 inches when he stopped it. Then, he put the water to come down slowly because he wasn’t sure how much more he needed. He let the water go for 2 minutes. Then, he stopped the water when it was at 12 inches of water. He sat in the bath for 5 minutes until he decided he was to cold so he hopped out. The water then drained really fast. From 12 inches to 0 inches it took the bath 3 minutes.

3 0

2 years ago

Anyone know how to find this answer

Kaylis [27]

The answer is a i hope i helped

4 0

2 years ago

Joan Messineo borrowed $47,000 at a 5% annual rate of interest to be repaid over 3 years. The loan is amortized into three eq

tester [92]

Answer:

a) The value of the Annual Payment is A=$17,258.80

b) Is the picture in the attachment file

c) As you can see it in the picture with each payment, balance comes down, due it is the interest base, Interest portion comes down too.

Step-by-step explanation:

Hi

a) First of all, we are going to list the Knowns: $VP=47000$ , $i=5$ % and $n=3$ , Then we can use $A=\frac{VP}{\frac{1-(1+i)^{-n} }{i} } =\frac{47000}{\frac{1-(1+0.05)^{-3} }{0.03} }=17258.80$ . So this is the value of the Annual Payment

6 0

2 years ago