The complete model for the given question is;
Number of fruit baskets that contain 12 fruits = 15 baskets
Number of fruit baskets that contain 15 fruits = 45 baskets
We are told that he bought 60 fruit baskets.
Percentage of the fruit baskets that have 12 pieces of fruit = 25%
Percentage of the fruit baskets that have 15 pieces of fruit = 75%
Thus;
Number of fruit baskets that contain 12 pieces of fruit = 25% × 60 = 15 baskets
Number of fruit baskets that contain 15 pieces of fruit = 75% × 60 = 45 baskets
Read more about percentages at; brainly.com/question/11865045
Step-by-step explanation:
-2(8m+8) = -16
-16m-16 = -16
-16m = -16+16
-16m= 0
m= 16
Therefore, the value of m is 16.
Sorry but is that below another question? or is it whole a same question?
-16m÷16 = -32÷16
-m = -2
remove those "-" signs from both sides. So, the answer is 2.
Part 1:
You have the correct answer. You multiply the probability of getting red (6/15) by the probailitiy of getting red (6/15) to get 36/225 which reduces to 4/25
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Part 2:
This is also correct. Nice work. You multiply the probability of getting black (9/15) with the probability of getting red (6/15) to get 54/225 = 6/25
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Part 3:
The probability of picking a black checker is 9/15. If a replacement is made, then the probability of picking another black checker is also 9/15. So,
(9/15)*(9/15) = 81/225 = 9/25
Answer: 9/25
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Part 4:
The probability of rolling a 6 is 1/6. The probability of rolling a 3 is 1/6 as well. This is because there is only one side with this label out of 6 total. Multiply the probabilities
(1/6)*(1/6) = 1/36
Answer: 1/36
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Part 5:
It is impossible to roll a 7 on the six sided cube because the highest number is 6. Therefore the overall probability is 0
Answer: 0
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Part 6:
There are 3 outcomes we want (rolling a 1,2, or 3) out of 6 total. So the probability of rolling a 1,2 or 3 is 3/6 = 1/2. Similarly, the probability of rolling a 4, 5 or 6 is 3/6 = 1/2 as well.
Multiplying the probabilities gives
(1/2)*(1/2) = 1/4
Answer: 1/4
Answer: Represent functions using function notation. MM1A1b: Graph the basic functions f(x) = xⁿ, where n = 1 to 3, f(x) = √x, f(x) = 1*1 and f(x) = 1∕x. ... MM1A1f: Recognize sequences as functions with domains that are whole numbers.
Step-by-step explanation:
