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ankoles [38]
3 years ago
11

For which data set would the median be a better measure of center than the mean?

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer:

I think D but I'm not 100 percent certain

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Twice a number is 12 more than 5 times the number.
stira [4]

Answer:

  • -4

Step-by-step explanation:

<u>Let the number be x:</u>

  • 2x = 5x + 12
  • 2x - 5x = 12
  • -3x = 12
  • x = -4

It is -4

5 0
3 years ago
I will give these ponts for free if u answer 100+100x100. (help me get brnliest)
Karolina [17]
In the beginning operations are performed with multiplication,,,so
100x100=10.000+100=
10.100result…
5 0
3 years ago
Passes through (1,9) slope=2
quester [9]

Answer:

y=2x+7

Step-by-step explanation:

y-y1=m(x-x1)

y-9=2(x-1)

y=2x-2+9

y=2x+7

4 0
3 years ago
A ball is kicked straight up into the air from a height of 48ft with an initial velocity of 88 ft/s. After how many seconds does
AlladinOne [14]

Answer:

67

Step-by-step explanation:

5 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
3 years ago
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