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Stella [2.4K]
3 years ago
11

A soup can that is a cylinder has a radius of 2x-1 and a height of 3x. What is the surface area of the soup can?

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
SA = ? 
<span>r = 2x - 1 </span>
<span>h = 3x </span>

<span>Then, </span>

<span>SA = 2π(2x - 1)² + 2π(2x - 1)(3x) </span>
<span>==> 2π(4x² - 4x + 1) + 6πx(2x - 1) </span>
<span>==> 8πx² - 8πx + 2π + 12πx² - 6πx </span>
<span>==> 20πx² - 14πx + 2π units² </span>
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6 0
3 years ago
The perimeter it a square field is 224. How long is
geniusboy [140]
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8 0
4 years ago
Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len
FromTheMoon [43]

Width of the miniature model = 3\frac{3}{4} inches

Length of the miniature model = 5\frac{1}{2} inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x

$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x

$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}

Do cross multiplication.

$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}

$\Rightarrow{\frac{15}{4}x =\frac{165}{2}

$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0
3 years ago
Find the rate of change of total​ revenue, cost, and profit with respect to time. Assume that​ R(x) and​ C(x) are in dollars. ​R
tresset_1 [31]

Answer:

Step-by-step explanation:

Given the Total revenue R(x) = 2x

Cost C(x) = 0.01x²+0.3x+30 where;

x = 30 and dx/dt = 9units per day.

Rate of change of revenue dR/dt = dR/dx • dx/dt

dR/dt = 2dx/dt

dR/dt = 2(9) = $18

Rate of change of revenue with respect to time is 18dollars/day.

Rate of change of cost dC/dt = dC/dx • dx/dt

dC/dt = (0.02x+0.3)dx/dt

dC/dt at x = 30 and dx/dt = 9 will give;

dC/dt = {0.02(30)+0.3}×9

dC/dt = (0.6+0.3) × 9

dC/dt = 0.9×9

dC/dt = $8.1

Rate of change of cost with respect to time is 8.1dollars/day

Profit = Revenue - Cost

Profit = 18-8.1

Daily Profit = $9.9

4 0
3 years ago
A Square was altered so that one side is increased by 9 inches in the other side is decreased by 2 inches.The area of the result
LekaFEV [45]

Let s represent the length of any one side of the original square.  The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.

The area of this rectangle is (s+9)(s-2) = 60 in^2.

This is a quadratic equation and can be solved using various methods.  Let's rewrite this equation in standard form:  s^2 + 7s - 18 = 60, or:

s^2 + 7s - 78 = 0.  This factors as follows:  (s+13)(s-6)=0, so that s = -13 and s= 6.  Discard s = -13, since the side length cannot be negative.  Then s = 6, and the area of the original square was 36 in^2.

4 0
3 years ago
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