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Jlenok [28]
3 years ago
13

2

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

9514 1404 393

Answer:

  Q'(-6, 9), R'(-9, 3), T'(6, -3), W'(6, 12)

Step-by-step explanation:

Each of the individual coordinate values is multiplied by 3.

  (x, y) ⇒ (3x, 3y)

__

  Q(-2, 3) ⇒ Q'(-6, 9)

  R(-3, 1) ⇒ R'(-9, 3)

  T(2, -1) ⇒ T'(6, -3)

  W(2, 4) ⇒ W'(6, 12)

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The Statue of Liberty is 305.5 feet tall from the foundation of its pedestal to the top of its torch. Isla is building a model o
Kisachek [45]

Answer:

30,550 feet.

Step-by-step explanation:    

We have been given that the Statue of Liberty is 305.5 feet tall from the foundation of its pedestal to the top of its torch. Isla is building a model of the statue. The model will be 100 times as tall as the actual statue.  

To find the height of statue we will multiply the height of Statue of Liberty by 100.

\text{The height of model}=100\times \text{The height of actual statue}

\text{The height of model}=100\times 305.5

\text{The height of model}=30,550

Therefore, the model statue will be 30,550 feet tall.

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3 years ago
Are the given values in the table enough information to show an exponential function instead of a linear function? If not, expla
BaLLatris [955]

Answer:

where is the table

Step-by-step explanation:

6 0
3 years ago
in a box of length 1m, breath 60cm, height 40cm. small rectangle packets of dimensions 5cm x 8cm x 10cm are packed. how many suc
Ulleksa [173]

Answer:

600 small packets

Step-by-step explanation:

First find the volume of the small packets:

5 x 8 x 10 = 400 cm³

Then find the volume of the big box:

100 x 40 x 60 = 240,000 cm³

Then divide the volume of the big box by the volume of the small packets:

240,000 ÷ 400 = 600 small packets

5 0
4 years ago
Read 2 more answers
the smaller rectangle is a 1/4 scale drawing of the original figure. Use the drop-down menus to show the missing dimensions of t
Neporo4naja [7]

Answer:

Part a) The length of the smaller rectangle is 6\ ft

Part b) The width of the smaller rectangle is 5\ ft

Part c) The area of the smaller rectangle is 30\ ft^{2}

Step-by-step explanation:

Part a)

<u>Find the length side of the smaller figure</u>

we know that

The scale factor is equal to \frac{1}{4}

Remember that

The scale factor is equal to divide the measure of the smaller figure by the corresponding measure of the original figure

so

Let

x--------> the length of the smaller rectangle

y-------> the length of the original figure

z-----> scale factor

z=\frac{x}{y}

we have

y=24\ ft

z=1/4

substitute and solve for x

(1/4)=\frac{x}{24}

x=24/4=6\ ft

Part b)

<u>Find the width side of the smaller figure</u>

we know that

The scale factor is equal to \frac{1}{4}

Remember that

The scale factor is equal to divide the measure of the smaller figure by the corresponding measure of the original figure

so

Let

x--------> the width of the smaller rectangle

y-------> the width of the original figure

z-----> scale factor

z=\frac{x}{y}

we have

y=20\ ft

z=1/4

substitute and solve for x

(1/4)=\frac{x}{20}

x=20/4=5\ ft

Part c)

<u>Find the area of the smaller figure</u>

we know that

The scale factor is equal to \frac{1}{4}

Remember that

The scale factor squared is equal to divide the area of the smaller figure by the area of the original figure

so

Let

x--------> the area of the smaller rectangle

y-------> the area of the original figure

z-----> scale factor

so

z^{2}=\frac{x}{y}

we have

y=480\ ft^{2}

z=1/4

substitute and solve for x

(1/4)^{2}=\frac{x}{480}

x=480/16=30\ ft^{2}

4 0
4 years ago
What is the vaulebof x<br>x-1/6=8​
nasty-shy [4]

Answer:

hopefully help and don't forget to give my Answer as a brainliest

5 0
3 years ago
Read 2 more answers
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