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Salsk061 [2.6K]
3 years ago
10

Can someone answer this for me

Mathematics
2 answers:
Kruka [31]3 years ago
4 0
75. The person above explained the math really well
scoundrel [369]3 years ago
3 0

Answer:

2.75x + 114 = 320.25

x = $75

Step-by-step explanation:

2.75x + 114 = 320.25

number of hours of labor (2.75) times the cost per hour of labor (x) + cost of parts (114) = total cost (320.25)

2.75x + 114 = 320.25

subtract 114 from both sides

2.75x = 206.25

divide both sides by 2.75

x = 75

------------------------

check the math:

2.75(75) = 114 = 206.25 + 114 = 320.25

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Jose bought a magazine for $6 and five notepads. He spent a total of $26. How much did each notepad cost?
bixtya [17]
4 dollars. 26-6=20. 20/5=4
8 0
3 years ago
Find AC.<br> Round to the nearest tenth.<br> B<br> 86°<br> 16<br> С<br> 11<br> A
Vadim26 [7]

Answer:

19.4

Step-by-step explanation:

16^2+11^2=377

then square 377 which will equal to

19.416 which can be rounded up to 19.4

6 0
3 years ago
Solve each triangle using the information provided. If necessary, round to the<br> nearest tenth.
Goryan [66]

Answer:

1) B = 66.5° c = 10.9

Step-by-step explanation:

I will do question one as an example. In general, for these questions you want to use the appropriate trigonometric ratios to solve for the variables and/or apply logic using rules regarding triangles. See attached image for all solving steps.

For side c, we can use Cosine of angle A for a ratio between 10 and c. When we write out the equation, we can solve for side c. So when we write it out, we get the equation:

cos23.5 = ¹⁰⁄c

c = ¹⁰⁄cos₂₃.₅

c = 10.9044 (make sure to round to the nearest tenth, which is one decimal place)

For angle B, since they have given two angles, you can solve for B since all angles of a triangle add up to 180 degrees.

So b = 180 - (90 + 23.5) = 180 - 113.5

b = 66.5

  • It is also possible to solve this using sine of angle B and solve it from there, but applying the theory this way is much simpler. (this is on the image if you're curious about it)

I hope this helps you with the other 3 questions.

4 0
3 years ago
Problem<br> How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?
olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

6 0
3 years ago
Which of the following equations matches the graph above?
Ierofanga [76]
Yes , I agree w them I’m gonna go with the answer D.
3 0
3 years ago
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