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3 years ago

I NEED HELP PLEASE IT WOULD REALLY MEAN AOT !!!! NO ZOOMS OR LINKS!!!!

Mathematics

1 answer:

Reika [66]3 years ago

5 0

Answer:

20.78

Step-by-step explanation:

sin a = perpendicular/ hypotenuse

where a is the base angle

here a = 60

sin 60 = 18/ x

since,

$\sin(60) = \ \frac{ \sqrt{3} }{2}$

$\frac{ \sqrt{3} }{2} = \frac{18}{x}$

√3 x = 36

x = 36/ √3

x = 36/ 1.732

x = 20.78

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t When you reverse the digitals in a certain number you increase its value by 27. Find the number if the sum fixes digits is 9.

TiliK225 [7]

The number=10x+y
we suggest this system of equations:
(10y+x)-(10x+y)=27
x+y=9 ⇒x=9-y

Can solve this system of equations by susbstitution method.
(10y+(9-y)-(10(9-y)+y)=27
10y+9-y-(90-10y+y)=27
10y-y+10y-y=27-9+90
18y=108
y=108/18
y=6

x=9-y
x=9-6
x=3

The number=10x+y=10(3)+6=36

Answer: the number is 36.

to check:
63-36=27
6+3=9

3 0

4 years ago

6 grade math pls help and do step by step

notka56 [123]

Jay didnt follow the BEDMAS rule, he should have started withe the division because it has the priority based on the BEDMAS rule.

8 0

3 years ago

HELP PLEASE PLEASE!!

Feliz [49]

9514 1404 393

Answer:

x = 21

Step-by-step explanation:

The parallel lines divide the segments proportionally.

x/27 = 28/36

x = 27(28/36) . . . . multiply by 27 (in your head: (3·9)(4·7)/(4·9) = 3·7)

x = 21

8 0

3 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$