Answer:
5
Step-by-step explanation:
Both side have to equal
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
10,20,40
Step-by-step explanation:
They all have a factor of 2,10, and 1
D. None. Say the obtuse angle is 100 degrees. Since the sum of all angles in a triangle cannot be bigger than 180, it's not possible because 195 (100+95) is greater than 180 degrees.
Hope this helps!!!!!!
Answer:
276 Guests
Step-by-step explanation:
Calculation to determine how many guest were at the wedding
Guests that choose beef =1/3
Guests that choose chicken= 5/12
Guests that choose vegetarian=69
Now let calculate the how many guest were at the wedding
Let x represent the numbers of guest that were present at the wedding
Hence,
x/3 + 5x/12 + 69 = x
9x/12 + 69 = x
12x/12 - 9x/12 = 69
3x/12 = 69
x/4 = 69
x=69*4
x = 276 guests
Therefore the numbers of guests that were at the wedding is 276
