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3 years ago

I NEED HELP PLEASE IT WOULD REALLY MEAN AOT !!!! NO ZOOMS OR LINKS!!!!

Mathematics

1 answer:

Reika [66]3 years ago

5 0

Answer:

20.78

Step-by-step explanation:

sin a = perpendicular/ hypotenuse

where a is the base angle

here a = 60

sin 60 = 18/ x

since,

$\sin(60) = \ \frac{ \sqrt{3} }{2}$

$\frac{ \sqrt{3} }{2} = \frac{18}{x}$

√3 x = 36

x = 36/ √3

x = 36/ 1.732

x = 20.78

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Please help me with all three! 25 Points!!

Gnoma [55]

a. 28 * 63

28 (60) + 28 (3) or 20 (60) +20 (3) + 8 (60) + 8 (3)

1680 + 84=1764 1200 / 60 +480 +24=1764

b. 17(59)

17 (50) + 17 (9) or 10 (50) + 10 (9) + 7 (50) +7 (3)

850 + 153=1003 500 + 90 + 63 =1003

c.458 (15)

458 (10) +458 (5) or 10 (400) + 10 (50) + 10 (8) + 5 (400) +5 (50) + 5 (8)

4580 +2290 = 6870 400 + 500 + 80 + 2000 + 250 + 40 = 6870

My work is kinda confusing but hope it helped

8 0

3 years ago

Harry’s basic rate is $22.00 per hour. If overtime is paid at time-and-a-half, how much will

kogti [31]

Answer:

33 dollors a hour I think I may be wrong

6 0

3 years ago

HELP PRECALC NEED IN PROOF FORM

Vinil7 [7]

Hello, please consider the following.

We know the following, right ?

$(\forall a, b \in \mathbb{R}) \left( sin(a+b)=sin(a)sin(b)+cos(a)cos(b) \right)$

So, here, it gives.

$Asin(\omega t+\phi)=Asin(\phi){\sf \bf sin(\omega t)}+Acos(\phi){\sf \bf cos(\omega t)}\\\\=c_2{\sf \bf sin(\omega t)}+c_1{\sf \bf cos(\omega t)}\\\\\text{ *** where }c_2=Asin(\phi) \text{ and } c_1=Acos(\phi) \text{ ***}$

Do not hesitate if you need further explanation.

5 0

4 years ago

If segment DE is 12, what is segment BC?

katovenus [111]

Answer:

A) 24

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP I NEED IT BEFPRE 11:59

Brut [27]

Step-by-step explanation:

If np is attitude

5x^2+10=90

5x^2=80

x^2=16

X=+-4

angle npo=90 degeees

3 0

3 years ago