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Lady_Fox [76]
3 years ago
13

HEY CAN ANYONE PLS ANSWER DIS MATH PROBLEM!!!!

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

y=-\frac{x}{2}+\frac{17}{2}

Step-by-step explanation:

hope this is what you are looking for

have a nice day!!

Nataly_w [17]3 years ago
3 0

Answer: y = (-1/2)x + 8.5

Step-by-step explanation:

A line perpendicular would have a slope that is the negative reciprocal of the given equation.

In this case, the slope is 2, so the perpendicular equation's slope would be -1/2.

We plug in (1, 8) to find b, or the y intercept.

8 = (-1/2)(1) + b

b = 8.5

So the equation would be:

y = (-1/2)x + 8.5

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Solve the formula V=3/4 LWH for W
aniked [119]
W= 3/4 divided by LH
5 0
3 years ago
1 point
Anton [14]

Answer:

  C.  350 miles

Step-by-step explanation:

Daphne wants to drive 3/4 of the distance in the first 2 days. So, her mileage per day should be about (3/4)/2 = 3/8 of the total mileage:

  (3/8)(932.4 mi) = 349.65 mi ≈ 350 mi

She should drive about 350 miles on each of the first 2 days.

8 0
3 years ago
A rectangular prism is filled with cubes that
Svet_ta [14]

Answer:

Find the volume of the rectangular prism and

divide by the volume of the cube.

Volume of cube = side measure ^3

Cube = (1/8)3 = 1/512

Volume of prism = Ixwxh

Prism (1/4)(1/2)(3/8) =3/64

3/64/1/512

3/64 x 512/1

3x 512/64

1536/64

24

6 0
2 years ago
SOMEONE PLEASE HELP!!!!
astra-53 [7]
Joint variation equation is a situation when the final value varies by two or more variables

Equation 1

A = s²

Here we have only one variable, 's', and the value of Area will only vary when s varies.

Equation 2

A = πr²

Here the only variable is 'r', which is the radius of a circle. The value of Area, A, varies as radius varies. π is a constant.

Equation 3

A = l×w

Here we have to variables, the 'l' and the 'w'. 
We can say that the value of Area, A, will vary jointly as l and w vary

The correct answer is option a)
3 0
3 years ago
A machine used to fill​ gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of ounces and a st
11111nata11111 [884]

Complete question is;

A machine used to fill gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of 128 ounces and a standard deviation of 0.20 ounce. You randomly select 35 cans and carefully measure the contents. The sample mean of the cans is 127.9 ounces. Does the machine need to be? reset? Explain your reasoning.

(yes/no)?, it is (very unlikely/ likely) that you would have randomly sampled 35 cans with a mean equal to 127.9 ?ounces, because it (lies/ does not lie) within the range of a usual? event, namely within (1 standard deviation, 2 standard deviations 3 standard deviations) of the mean of the sample means.

Answer:

Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

Step-by-step explanation:

We are given;

Mean: μ = 128

Standard deviation; σ = 0.2

n = 35

Now, formula for standard error of mean is given as;

se = σ/√n

se = 0.2/√35

se = 0.0338

Normally, the range of values should be within 2 standard deviations of mean. In this case, normal range of values will be;

μ ± 2se = 128 ± 0.0338

This gives; 127.9662, 128.0338

So, Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

4 0
3 years ago
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