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azamat
2 years ago
8

The function f(x) = -x^2 + 4x - 3 is graphed in the xy-coordinate plane as shown

Mathematics
1 answer:
Sidana [21]2 years ago
3 0

Answer: im not sure but i got x2-4x-3

Step-by-step explanation:

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Kyle claimed that the given quadrilaterals are similar because the ratio of their corresponding sides is equal. Is Kyle's claim
Savatey [412]
The claim made by Kyle is not entirely true and unjustifiable because for the figures or solids to be similar, not only the corresponding sides should have the finite ratio but also the corresponding angles should be equal. Although, the claim depends on the type of quadrilateral. 
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Subtracting mixed number 4_1 - 2_7 4 8 4
aleksandr82 [10.1K]

Answer:

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

Step-by-step explanation:

Given

4\frac{1}{4} - 2\frac{7}{8} --- proper representation of the question

Required

Evaluate

Convert numbers to improper fractions

4\frac{1}{4} - 2\frac{7}{8} = \frac{17}{4} - \frac{23}{8}

Take LCM

4\frac{1}{4} - 2\frac{7}{8} = \frac{34 - 23}{8}

4\frac{1}{4} - 2\frac{7}{8} = \frac{11}{8}

Convert to improper fraction

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

8 0
3 years ago
What is the image of (3,9) after a dilation by a scale factor of 3 centered at the origin
Sav [38]

Answer:

(9, 27 )

Step-by-step explanation:

Since the dilatation is centred at the origin, multiply each of the coordinates of the original point by the scale factor of 3

(3, 9 ) → (3(3), 3(9)) → (9, 27 )

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-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

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answer is not possible
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