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nikdorinn [45]
2 years ago
9

Kelly works two jobs. She usually works at a retail store for 7 hours during the day and is paid $22.22 per hour by the store. I

n the evening she works at a restaurant as a manager for 7 hours and is paid $13.55 per hour. How much does she make on average per hour for the day? ​
Mathematics
2 answers:
lesantik [10]2 years ago
7 0
250.29 just add and multiply
Ede4ka [16]2 years ago
6 0

Answer:

Hey,

so if she works for seven hours at <em><u>both</u></em> jobs then we multiply how much she gets paid per hour times seven or 22.22*7=<em><u>155.54</u></em> and 13.55*7=<em><u>94.85</u></em>. Then we add what is underlined, 155.54+94.85= our answer which is <em><u>250.39</u></em> per day.

Wbob1314 hope it helped

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Answer:

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Step-by-step explanation:

Given

See attachment

Required

The probability that a 7th grader selected will play guitar.

From the attachment, we have:

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Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

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c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

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P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

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P(Y>1)=1- P(Y=0)

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P(Y>1)=1-0.349=0.651

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