1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
3 years ago
8

A. find the areab. find the perimeter​

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

Area= 4y^2 + 14y + 12

Perimeter = 10y + 16

Step-by-step explanation:

Area of a reactangle = length × width

= (4y+6) × (y+2)

= 4y^2 + 6y + 8y + 12

= 4y^2 + 14y + 12

Perimeter of a rectangle = 2 × (a +b)

= 2 × ( 4y + 6 + y+ 2)

= 2 × ( 5y + 8)

= 10y + 16

You might be interested in
Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected.
Leno4ka [110]

As the problem indicates, degrees of freedom are the number of values ​​that can be independently selected before it is necessary to choose specific values ​​to arrive at the desired result.

The average, on the other hand, results from the sum of a list of values ​​divided by the amount of values ​​in the summed list.

Assume that the mean sought is x and consider that the list is composed of a single element a, in that case no random number can be selected, since the mean x must correspond to that number.

If the list were composed of two elements a and b, one of the two values ​​could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in 2x, this given that the formula of the average \sum\limits_{i=1}^n \frac{ x_{i}}{n}.

With three values ​​a, b and c, it is possible to select two freely, since the thirteen must be the one that balances the sum of a+b, that is (a + b) + c = 3x.

Thus, in general, with n values, it is possible to select n-1 values ​​freely whose sum must be balanced by the last value so that the whole sum is nx.

Answer

In a list of \bf{n} values ​​you can assign \bf{n-1} values ​​freely, that is, you have n-1<em>degrees of freedom.</em>

6 0
3 years ago
Plz help i need help
Nataliya [291]

Answer: what the is dis sorry dont know

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A rectangle's length, x, is 2 meters greater than its width. If the perimeter of the rectangle is greater than 112 meters, what
Harman [31]

Answer:

The possible length is greater than 29 meters.

Step-by-step explanation:

If the length is x then the width is x - 2  m.

So the perimeter is 2x + 2(x - 2) = 4x - 4 m.

4x - 4 > 112

4x > 116

x > 29 m.

7 0
3 years ago
Why is the simplified value of the expression below? -8*(-3)
kirill115 [55]
When you multiply two numbers which have the same sign the answer is positive. Therefore multiply eight and three to get 24 and the answer is positive; therefor the answers 24.
8 0
3 years ago
Solve for x: 2 over 3 equals 8 over quantity x plus 6
SashulF [63]

Answer:

x = 40/3

Step-by-step explanation:

2/3 = (8/x) + 6

-6                -6

2/3 - 6 = -16/3

-16/3 = 8/x

*x          *x

(-16/3)x = 8

+16/3     +16/3

x = 40/3

7 0
3 years ago
Read 2 more answers
Other questions:
  • Austin brought 2,500 grams of red apples and 3,500 grams of Green apple.How many kilograms of apples did austin buy?
    9·1 answer
  • What does math anxiety mean?
    12·1 answer
  • Is this proportional
    15·2 answers
  • What is the best estimate of an area of circle with a radius of 7.62 m
    12·1 answer
  • What is the surface area of a cylinder with base radius 444 and height 555?
    5·1 answer
  • Help me its so hard to understand
    13·2 answers
  • What is the quotient
    15·1 answer
  • H(x) = 4x-2, then which of the following is the solution to h(x)= 3
    7·1 answer
  • Simplify ,without using a calculator(2 1/2)2 + (0.5)2 ​
    15·2 answers
  • Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!