Question

What is the probability of spinning a odd number, flipping heads, then spinning a 3?

Answer 1

Answer:   0

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Explanation:

The sample space of the spinner is {1,2,3,4,5,6,7,8,9} which represents all the possible outcomes. We can only pick one of those values. Of that list, the subset {1,3,5,7,9} represents all the odd numbers. This is the event space because we want to land on an odd number.

There are 5 items in the event space and 9 items in the sample space. The probability of getting an odd number is 5/9.

The probability of flipping heads is 1/2 since we have one side we want (heads) out of two sides total.

Lastly, the probability of landing on a '3' is 1/9 because there's only one '3' out of 9 values total.

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We'll multiply those fractions to get the final answer. This works because each event is independent of one another.

(5/9)*(1/2)*(1/9) = (5*1*1)/(9*2*9) = 5/162

Now use your calculator to find that: 5/162 = 0.030864 approximately which rounds to 0.0 or just 0 when rounding to the nearest tenth.

Unfortunately this is one case where rounding will creates a misleading result. The true probability isn't 0 because the events described are possible. The probability is just really small.

Answer 2

Answer:

Probability of spinning a odd number is 5/9

I don't know about flipping head

Probability of spinning a 3 is 1/9