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shtirl [24]
2 years ago
11

Can someone please help meee

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Step-by-step explanation:

Well the first 3 you just plug in the value of x which results in.

a. f(0) = 7(0)^2 + 3(0) - 2

   f(0) = -2

b. f(2) = 7(2)^2 + 3(2) - 2

   f(2) = 7(4) + 6 - 2

   f(2) = 28 + 4

   f(2) = 32

c. f(-2) = 7(-2)^2 + 3(-2) - 2

   f(-2) = 7(4) - 6 - 2

   f(-2) = 28 - 8

   f(-2) = 20

for the last ones it's essentially the same thing except the value a is not known

d. f(a+1) = 7(a+1)^2 + 3(a+1) - 2

   f(a+1) = 7(a^2 + 2a + 1) + 3a + 3 - 2

   f(a+1) = 7a^2 +14a + 7 + 3a + 1

   f(a+1) = 7a^2 + 17a + 8

c. f(-a) = 7(-a)^2 + 3(a) - 2

   f(-a) = 7a^2 + 3a - 2

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