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Art [367]
3 years ago
6

Write an equation for the line with a y-intercept of

Mathematics
1 answer:
jasenka [17]3 years ago
5 0

Answer:

The answer to the question provided is possibly y =  -  \frac{3}{4} x + 2.

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How the solve 14% of 27
iogann1982 [59]

Answer:

3.78

Step-by-step explanation:

How you do this problem is by simply multiplying 14% by 27. You have to remember that 14% is equivalent to 0.14, so you have to do 0.14 * 27 and you will get 3.78.

7 0
3 years ago
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Find the solution set
Katyanochek1 [597]

Answer:

-25,-25

Step-by-step explanation:

5 to the second is 25 . because 5 times 5 is 25

6 0
3 years ago
If (m,2m+1) is a solution of the equation 4x +2y=8 then the value of m
kirill115 [55]

Answer:

the answer would be m = 0.75

Step-by-step explanation:

hope it helps:)

3 0
3 years ago
A grocery store advertises that 15 cups of granola cost $6.75. Which are equivalent prices
fgiga [73]

which of what are equivilent prices?

6 0
4 years ago
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What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
antiseptic1488 [7]

Check the picture below.  So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as  you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5

6 0
3 years ago
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