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3 years ago

In 2015, there were approximately 33,400 firearm fatalities (homicide and suicides) Express this quantity in deaths per hour

1 answer:

4 0

8765.82 are how many hours there are in a year take that divided by 33400 and you get 3.81025392 or rounded up it would be 4 deaths per hour or just 3.8 per hour

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Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

$P(x=r)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

$P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}$

$=56(0.4)^5 (0.6)^3$

$=0.12386304$

(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

$=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8$

$=0.04980736$

(c) the probability of the number that say they would feel secure is at most five

$P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)$

$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$

$=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3$

$=0.95019264$

8 0

3 years ago

PLEASE HELP ME I NEED HELP ON THESE MATH PROBLEMS

Feliz [49]

Answer:

gurl download Symbolab right now!!

4 0

3 years ago

The nature of a graph, which has an even degree and a positive leading coefficient will be

zaharov [31]

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.

y = f(x) = 2x²+ 4

The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.

Learn more about the graph of a quadratic equation here:

brainly.com/question/9643976

#SPJ1

6 0

2 years ago

PLEASE HELP ASAP Will mark Brainliest as well

Nastasia [14]

4 and 8 are corresponding angles. Corresponding angles are on the same side of parallel lines cut by a transversal

4 0

3 years ago

A race track is made from two straights and two semicircles. The straights are 80m long. The race track has a total perimeter of

Dmitriy789 [7]

Answer:

76.4 m

Step-by-step explanation:

The race track has two straights and two semi circles.

Each straight is 80m

total perimeter for the straights is 80 * 2 = 160m

two semi circles which creates a full circle

perimeter of a full circle = $\pi$ d

NB : (d) is the diameter

therefore we can find the value of the diameter

400 = 160 + $\pi$ d

400- 160 = $\pi$ d

240 = $\pi$ d

d = 240/ $\pi$

d = 76.394.....

<u>d = 76.4 m</u>

3 0

3 years ago