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vazorg [7]
3 years ago
11

Solve for x and explain how I show work

Mathematics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

x = 100

Step-by-step explanation:

(x - 20) + x = 180  

2x - 20 = 180

<u>    + 20    +20</u>

2x = 200

x = 200/2

x = 100

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MissTica
It means the ball did not move forward or backward. It stayed on the same line where it was
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3 years ago
HELP PLEASEE<br> I’m stuck
Sever21 [200]

Answer:

:-):-)

Step-by-step explanation:

1) p<1000

2)p>500

3)By combining the above two, we get: 500<p<1000

Andre will agree as he thinks that the no. of paper clips in the box is less than 1000. But lin will not as she thinks that the no. of clips is more than 500.

4)This time, they both will agree as the no. of paper clips is more than 500 but less than 1000.

6 0
3 years ago
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Please answer question below <br> Thanks
slega [8]
5x+17+15=45
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5 0
3 years ago
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
Two long jumpers competed in a world-class track meet. The first athlete jumped a distance of 28.65 feet, and the second athlete
ladessa [460]
Hello! This is actually pretty easy to solve, all you have to do is subtract 28.65 from 24.25 So when you subtract 5 from 5, you get zero. When you subtract 6 from 2, you get 4. When you subtract 8 from 4, you get 4, and when you subtract 2 from 2 you get zero. So all you do is take out the zeros and put the decimal point in the same place it was in before, and this should leave you with your answer!

I hope this helped!

I am, yours most sincerely,
SuperHelperThingy
7 0
3 years ago
Read 2 more answers
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