When n = 1, 2(1) + 1 = 3
When n = 2, 2(2) + 1 = 5
When n = 3, 2(3) + 1 = 7
When n = 4, 2(4) + 1 = 9
When n = 5, 2(5) + 1 = 11
Sum = 3 + 5 + 7 + 9 + 11 = 35
----------------------------------------------------
Answer: 35
----------------------------------------------------
Answer:for #2 it's answer 1. #3 is " five less than twice a number is 2x-5. Then 5 times the sum of two numbers if 5x+y. The the difference of 5 and a number squared is (5-x)*2
Step-by-step explanation:
Hope this helps
Answer:
The 4 t h term is f(4) = 143
Step-by-step explanation:
<em>Explanation</em>:-
Given function f(1) = -4
Given 'nth' term is f(n) = -3f(n-1) +5
Put n =2 <em> f(2) = -3 f(2-1) +5</em>
= -3 f(1) +5
= -3 (-4) +5
= 12 +5
f(2) = 17
put n= 3
f(n) = -3f(n-1) +5
<em> f(3) = -3 f(3-1) +5</em>
= -3f(2) +5
= -3(17) +5
= -51+5
f(3) = -46
Put n=4
f(n) = -3f(n-1) +5
<em> f(4) = -3f(4-1) +5</em>
<em> f(4) = -3f(3)+5</em>
f(4) = -3(-46)+5
f(4) = 138 +5
f(4) = 143
<u><em>Final answer</em></u>:-
<em>The 4 t h term is f(4) = 143</em>
Answer:
x2 = -0.600000
x3 = -0.521600
Step-by-step explanation:
Given the formula;
xn+1 = (xn)³-5/10
x2 = (x1)³-5/10
Given x1 = -1
x2 = (-1)³-5/10
x2 = (-1-5)/10
x2 = -6/10
x2 = -0.600000
x3 = (x3)³-5/10
Given x3 = -0.6
x3 = (-0.6)³-5/10
x3 = (-0.216-5)/10
x3 = -5.216/10
x3 = -0.521600
