Answer:
Case n =5
Case n =15
Case n = 40
P value
Case n =5
Case n =15
Case n =40
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the population standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
z would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:
(1)
z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Case n =5
Case n =15
Case n = 40
P-value
Since is a left tailed test the p value would be:
Case n =5
Case n =15
Case n =40
Answer:
x= -9......................
Answer:
8%
Step-by-step explanation:
0.36/4.50=0.08=8%
Answer:
i think its d
Step-by-step explanation:
Answer:
Option (B) is the correct answer to the following question.
Step-by-step explanation:
Step-1: We have to find the Mean of the series.
The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

Step-2: We have to find the Standard Deviation.
Let Standard Deviation be x.
Formula of Standard Deviation is: 
Put value in formula of Standard Deviation,
= 40.75
Step-3: Then, we have to find the critical value by chi-square.


Then, find the confidence interval which is 95%.

