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choli [55]
3 years ago
11

Solve the equation or formula for the variable specified 8qr+4t=7u for q ?

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer:

q= −4t+7u  over 8r

Step-by-step explanation:

8qr+4t=7u

Step 1: Add -4t to both sides.

8qr+4t+−4t=7u+−4t

8qr=−4t+7u

Step 2: Divide both sides by 8r.

8qr

8r

=

−4t+7u

8r

q=

−4t+7u

8r

Answer:

q=

−4t+7u

8r

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I need help . This problem is confusing me.<br><br>​
Sholpan [36]

Answer:

The answer is 3093.

3093 (if that series you posted actually does stop at 1875; there were no dots after, right?)

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We have a finite series.

We know the first term is 48.

We know the last term is 1875.

What are the terms in between?

Since the terms of the series form a geometric sequence, all you have to do to get from one term to another is multiply by the common ratio.

The common ratio be found by choosing a term and dividing that term by it's previous term.

So 120/48=5/2 or 2.5.

The first term of the sequence is 48.

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The third term of the sequence is 48(2.5)(2.5)=300.

The fourth term of the sequence is 48(2.5)(2.5)(2.5)=750.

The fifth term of the sequence is 48(2.5)(2.5)(2.5)(2.5)=1875.

So we are done because 1875 was the last term.

This just becomes a simple addition problem of:

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