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olga_2 [115]
3 years ago
6

Maya has a car loan of $31,470. The loan has a simple interest rate of 5% per year.

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

$1573.50

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 31470 × 0.05 × 1 = 1573.5

I = $ 1,573.50

The simple interest accumulated

on a principal of $ 31,470.00

at a rate of 5% per year

for 1 year is $ 1,573.50.

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Step-by-step explanation:

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Which shows an angle that is approximately 80°?
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I would say B. The second picture, it's slightly less than a 90 degree angle, so it looks like it should be that.  

Hope this helps!! :)
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The cost of a repair, which depends on the hours it takes to make the repair, is $200. Which of the following best shows this in
Rzqust [24]

The answer would be A.


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3 years ago
The product of two positive numbers is 120. One number is 7 more than the other. Determine the two numbers
Sati [7]
Xy= 120
x= 7+y

(7+y)(y) = 120
y^2 + 7y - 120 = 0
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3 years ago
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
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