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kap26 [50]
3 years ago
12

I need help with this question. all of it is a single question​

Mathematics
1 answer:
pashok25 [27]3 years ago
7 0

Answer:

o uh

Step-by-step explanation:

so im sorry im not in college my friend. i see ur in ap, but uh im only 6th

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PLEASE HELP ILL GIVE MORE IF ITS RIGHT
Roman55 [17]

Answer:

choice 3) area = 1188 in²

Step-by-step explanation:

area = 36 x 33 = 1188 in ²

7 0
3 years ago
What is the perimeter of rhombus WXYZ?
oksian1 [2.3K]

<u>Answer</u>:

The perimeter of rhombus WXYZ is 4 \sqrt{13}

<u>Step-by-step explanation:</u>

Step 1 :Finding length  of  XY

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 5

x_2=3

y_1= -1

y_2=2

XY  = \sqrt{(3-5)^2 +(2 -(-1))^2}

XY  = \sqrt{(3-5)^2 +(2 +1))^2}

XY  = \sqrt{(-2)^2 +(3))^2}

XY  = \sqrt{4 +9}

XY  = \sqrt{(13)}

Step 2 :Finding length  of  YZ

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 3

x_2=5

y_1= 2

y_2=5

YZ  = \sqrt{(5-3)^2 +(5-2)^2}

YZ = \sqrt{(2)^2 +(3)^2}

YZ = \sqrt{4 +9}

YZ  = \sqrt{(13)}

Step 3 : :Finding length  of  ZW

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 5

x_2=7

y_1= 5

y_2=2

ZW = \sqrt{(7-5)^2 +(5-2)^2}

ZW  = \sqrt{(2)^2 +(3)^2}

ZW  = \sqrt{4 +9}

ZW = \sqrt{(13)}

Step 4 :Finding length  of  WX

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 7

x_2=5

y_1= 2

y_2= -1

WX = \sqrt{(7-5)^2 +((-1)-2)^2}

WX  = \sqrt{(2)^2 +(-3)^2}

WX  = \sqrt{4 +9}

WX = \sqrt{(13)}

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> 4 \times \sqrt{13}

=> 4 \sqrt{13}

5 0
3 years ago
Read 2 more answers
3x^2 - 5x + 12 <br> 5x^2 + x - 11
Effectus [21]

Answer:

8x²+5x+1

Step-by-step explanation:

3x²-5x+12

5x²+ x - 11

________

3x²+5x²= 8x²

}

5x+x =5x

}

12-11 =1

=

8x²+5x+1

7 0
3 years ago
The sum of 4 consecutive integers is 182. W hat is the sum of the middle two numbers?
Kamila [148]

Answer:

91

Step-by-step explanation:

Let

x = first number

x+1 = second number

x+2 = third number

x+3 = fourth number

Total = 182

x + x + 1 + x + 2 + x + 3 = 182

4x + 6 = 182

Subtract 6 from both sides

4x + 6 - 6 = 182 - 6

4x = 176

Divide both sides by 4

x = 176 / 4

= 44

x = 44

x = 44

x+1 = 44 + 1 = 45

x+2 = 44 + 2 = 46

x+3 = 44 + 3 = 47

Sum of the two middle numbers = 45 + 46

= 91

8 0
3 years ago
3. Maria is a veterinarian. She wants to know how the weight of a puppy is related to its length. To find out, Maria randomly se
sweet [91]

Answer:

Part A. I chose points (7,1.3) and (48,9.8)

Part B. a. Positive correlation; b.  y = 0.21x - 0.2

Step-by-step explanation:

Part A.

I chose the first and last points on the line — (7 in, 1.3 lb) and (48 in, 9.8 lb).

That put three points on the line, three above it, and four below.

Part B

a. Type of correlation

There is a positive correlation between the length of a puppy and its weight.

You would expect a longer dog to be bigger and weigh more than a shorter dog.

b.  The equation for the line of best fit

The slope-intercept equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (7,1.3) and (48, 9.8).

(i) Calculate the slope of the line

\begin{array}{rcl}

m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{9.8 - 1.3}{48-9}\\\\& = & \dfrac{8.5}{41}\\\\& = & \textbf{0.21 lb/in}\\\\\end{array}

The slope of the line is 0.21 lb/in.

(ii) Locate the y-intercept

Put the slope and the coordinates of one point into the slope-intercept formula.

\begin{array}{rcl}y & = & mx + b\\1.3 & = & 0.21\times7 + b\\1.3 & = & 1.47 + b\\b & = & -0.2\\\end{array}

The y-intercept is at (0,-0.2)

(iii) Write the equation for the line

y = 0.21x - 0.2

5 0
3 years ago
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