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3 years ago

3x^2 - 5x + 12 5x^2 + x - 11

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

Answer:

8x²+5x+1

Step-by-step explanation:

3x²-5x+12

5x²+ x - 11

________

3x²+5x²= 8x²

}

5x+x =5x

}

12-11 =1

8x²+5x+1

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How many liter of 15% weed killer mixture must be added to 5 liters of 10% weedkiller mixture to make 12% weed killer mixture?

finlep [7]

Answer: 3 1/3 liter

Brainliest? <3

let x equal the number of liters of 15% weedkiller.

your equation is .15 * x + .10 * 5 = .12 * (x + 5)

simplify to get .15 * x + .10 * 5 = .12 * x + .12 * 5

simplify further to get .15 * x + .5 = .12 * x + .6

subtract .12 * x from both sides and subtract .5 from both sides and simplify to get .03 * x = .1

divide both sides by .03 to get x = .1 / .03 = 3.333333333 rounded to 9 decimal digits.

you would need 3.333333333 liters of 15% solution to be added to 5 liters of 10% solution to get 8.333333333 liters of 12% solution.

.15 * 3.333333333 = .5

.10 * 5 = .5

.5 + .5 = 1

5 + 3.333333333 = 8.333333333

1 divided by 8.333333333 = .12 which is equal to 12%.

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3 years ago

A random walk on the 2-dimensional integer lattice begins at the origin. At each step, the walker moves one unit either left, ri

NNADVOKAT [17]

The 9 combinations that exist for two movements:

R,R
R,L
R,U *
L,R
L,L
L,U
U,R *
U,L
U,U

Walker would only be able to make it to (1,1) with only 2 of these combinations.

So if he were only allowed to make two movements, his chances of arriving at (1,1) would be 2/9.

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3 years ago

The distance between flaws on a long cable is exponentially distributed with mean 12 m.

Elden [556K]

Answer:

(a) The probability that the distance between two flaws is greater than 15 m is 0.2865.

(b) The probability that the distance between two flaws is between 8 and 20 m is 0.3246.

(d) The standard deviation is 12.

(e) The 65th percentile of the distances is 12.61 m.

Step-by-step explanation:

The random variable X can be defined as the distance between flaws on a long cable.

The random variable X is exponentially distributed with mean, μ = 12 m.

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{12}=0.0833$

The probability density function of X is:

$f_{X}(x)=0.0833e^{-0.0833x};\ x\geq 0$

(a)

Compute the probability that the distance between two flaws is greater than 15 m as follows:

$P(X\geq15)=\int\limits^{\infty}_{15}{0.0833e^{-0.0833x}}\, dx\\=0.0833\times \int\limits^{\infty}_{15}{e^{-0.0833x}}\, dx\\=0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{\infty}_{15}\\=e^{0.0833\times 15}\\=0.2865$

Thus, the probability that the distance between two flaws is greater than 15 m is 0.2865.

(b)

Compute the probability that the distance between two flaws is between 8 and 20 m as follows:

$P(8\leq X\leq20)=\int\limits^{20}_{8}{0.0833e^{-0.0833x}}\, dx\\=0.0833\times \int\limits^{20}_{8}{e^{-0.0833x}}\, dx\\=0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{20}_{8}\\=e^{0.0833\times 8}-e^{0.0833\times 20}\\=0.51355-0.1890\\=0.32455\\\approx0.3246$

Thus, the probability that the distance between two flaws is between 8 and 20 m is 0.3246.

(c)

The median of an Exponential distribution is given by:

$Median=\frac{\ln (2)}{\lambda}$

Compute the median as follows:

$Median=\frac{\ln (2)}{\lambda}$

$=\farc{0.69315}{0.08333}\\=8.322$

Thus, the median is 8.322.

(d)

The standard deviation of an Exponential distribution is given by:

$\sigma=\sqrt{\frac{1}{\lambda^{2}}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{\frac{1}{\lambda^{2}}}$

$=\sqrt{\frac{1}{0.0833^{2}}}\\=12.0048\\\approx 12$

Thus, the standard deviation is 12.

(e)

Let x be 65th percentile of the distances.

Then, P (X < x) = 0.65.

Compute the value of x as follows:

$\int\limits^{x}_{0}{0.0833e^{-0.0833x}}\, dx=0.65\\0.0833\times \int\limits^{x}_{0}{e^{-0.0833x}}\, dx=0.65\\0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{x}_{0}=0.65\\-e^{-0.0833x}+1=0.65\\-e^{-0.0833x}=-0.35\\-0.0833x=-1.05\\x=12.61$

Thus, the 65th percentile of the distances is 12.61 m.

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3 years ago

You need to remove a tree from your front yard. You have climbed the tree and trimmed off the branches, and you are now ready to

ValentinkaMS [17]

Answer:

26 feet

Step-by-step explanation:

Let the length of the required wire =l

The height of the tree =24 cm

We want the tree to fall to the ground 10 feet away from the base.

Ths problem forms a right triangle which I have drawn and attached below.

To determine the length of the wire l required, we use Pythagoras theorem to solve for the hypotenuse of the right triangle.

$B$y Pythagoras theorem: Hypotenuse^2=Opposite^2+Adjacent^2\\$Therefore:\\l^2=24^2+10^2\\l^2=676\\$Take the square root of both sides\\l=\sqrt{676}\\ l=26$ feet$

Thw wire must be 26 feet long to reach the ground.

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3 years ago

Whats the ANSWER GIVING BRAINLIEST TO RIGHT ONE:)

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Answer:

Step-by-step explanation:

I believe this is the correct one.

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