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2 years ago

10

A triangle has sides with lengths of 16 centimeters, 23 centimeters, and 24 centimeters. Is it a right triangle?

1 answer:

Goshia [24]2 years ago

4 0

A triangle has sides with lengths of 16 centimeters, 23 centimeters, and 24 centimeters. Is it a right triangle?

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Solve the system of equations <br><br> Y= -7x+3<br> Y= -x -3<br><br> What is X<br> What is Y

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The answer is X = 1 and Y = -4.

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2 years ago

Is 1/2x -1 equivalent to 2/3(3/4x-3/2)

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Flauer [41]

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D, the last answer choice

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3 years ago

Read 2 more answers

Select from the drop-down menus to correctly complete each statement.

shtirl [24]

The opposite of 17.2 from 0 on a number line would be -17.2.

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3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

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2 years ago