The area of a rhombus is computed as follows:
A = p*q*1/2
where p and q are the diagonals of the rhombus.
In this case:
A = AC*BD*1/2
A = 6*4*1/2
A = 12 square inches
Answer:
cos(pi/2) + i sin (pi/2)
Step-by-step explanation:
(1+i)/ (1-i)
Multiply top and bottom by (1+i)
(1+i) (1+i)/ (1-i)(1+i)
Foil the top (1+i)(1+i) = 1 +2i +i^2 = 1 +2i -1 = 2i
Foil the bottom ( 1+i)(1-i) = 1 - i^2 = 1 - (-1) =2
2i/2 = i
the magnitude is (0^2+1^2) = 1
The angle is tan^-1( 1/0) = pi/2
cos(pi/2) + i sin (pi/2)
Answer:
P' = (3, 0)
Step-by-step explanation:
You are translating the point (x, y) of (5, -5) to the left 2 units and up 5 units. The x value changes when shifting left or right. So the x value shifts to the left 2 units, meaning it shifts left on the number line, so it reduces by 2 units. The y value changes when shifting up or down. So the y value shifts up 5 units, so it increases in value by 5 units
