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Tema [17]
3 years ago
14

Finit set: 1+2+3+........+25=??

Mathematics
2 answers:
yulyashka [42]3 years ago
6 0

Answer:

Finite set: A set is said to be a finite set if it is either void set or the process of counting of elements surely comes to an end is called a finite set.

In a finite set the element can be listed if it has a limited i.e. countable by natural number 1, 2, 3, ……… and the process of listing terminates at a certain natural number N.

The number of distinct elements counted in a finite set S is denoted by n(S). The number of elements of a finite set A is called the order or cardinal number of a set A and is symbolically denoted by n(A).

Thus, if the set A be that of the English alphabets, then n(A) = 26: For, it contains 26 elements in it. Again if the set A be the vowels of the English alphabets i.e. A = {a, e, i, o, u} then n(A) = 5.

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
5 0

1+2+3+4+5+6..........23+24+25=325

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3 years ago
Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)
enyata [817]

Answer:

We conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

Step-by-step explanation:

Given the expression

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)

Remove parentheses: (a) = a

=3\times \:2x+4\times \:5y+4\times \:2z

Multiply the numbers: 3 ×  2 = 6

=6x+4\times \:5y+4\times \:2z

Multiply the numbers: 4 × 5 = 20

=6x+20y+4\times \:2z

Multiply the numbers: 4 × 2 = 8

=6x+20y+8z

Thus, we conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

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3 years ago
Which numbers are irrational?
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3 years ago
A farmer has 1800 m of fencing. He needs to create
NeTakaya

Answer:

67,500 m²

Step-by-step explanation:

ASSUMING the fields look like this __________________

                                                            |                    |                   |

                                                            |                    |                   | W

                                                            |_________|_________|

                                                                                L                                                            

Let L be the length of the combined field and W be the width

2L + 3W = 1800

2L = 1800 - 3W

L = 900 - 1.5W

A = LW

A = (900 - 1.5W)W

A = 900W - 1.5W²

Area will be maximized when the derivative equals zero.

dA/dW = 900 - 3W

        0 = 900 - 3W

     3W = 900

       W = 300 m

L = 900 - 1.5(300)

L = 450 m

A = LW = 450(300) = 135,000 m²

so each sub field is 135000/2 = 67,500 m²

7 0
3 years ago
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