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Andru [333]
3 years ago
7

The regular price of a baseball hat is 14.45$. If Carlos buys the baseball hat on sale for 20% off the regular price, how much c

hange will he receive after paying with 20$
Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

$8.44

Step-by-step explanation:

To find the 20%

x/14.45=20/100

14.45×20=289

289÷100=2.89

We then subtract 2.89 from 14.45 to get the selling price.

14.45-2.89=11.56

$11.56 is the price of the baseball hat on sale.

To get the change

20-11.56=8.44

$8.44 is the change

<u><em>I</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helped</em><em>!</em><em> </em><em>:</em><em>)</em></u>

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pentagon [3]
1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
4 0
3 years ago
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Vikentia [17]
Use the communicative property of addition to switch to order and you get
13 - 5, so the answer is 8, or k = 8

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3 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
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WITCHER [35]
Divide by each number below it and find that each does not come out to a whole number except for dividing by 1
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3 years ago
I am very stuck with this
Bingel [31]

Answer:

see explanation

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To multiply the vector by a scalar, multiply each of the elements by the scalar.

To add 3 vectors add the corresponding elements of each vector

2a + 3b + 4c

= 2\left[\begin{array}{ccc}2\\3\\\end{array}\right] + 3\left[\begin{array}{ccc}-4\\1\\\end{array}\right] + 4\left[\begin{array}{ccc}3\\2\\\end{array}\right]

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