Answer:
Therefore the probability that a pen from the first box and a crayon from the second box are selected is 
Step-by-step explanation:
Probability:
The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

Given that,
Three plain pencils and 5 pens are contained by the first box.
Total number of pens and pencils is =(3+5)=8
The probability that a pen is selected from the first box is
=P(A)


A second box contains three colored pencils and three crayons.
Total number of pencils and crayons is =(3+3)=6
The probability that a crayon is selected from the second box is
=P(B)


Since both events are mutually independent.
The required probability is multiple of the events
Therefore the required probability is


Answer:
first side=40
second side=20
third side=22
Step-by-step explanation:
LET THE SIDES OF THE TRIANGLES BE y
Perimeter=82
first side=2 x y = 2y
second side=y
third side=2 +y
2y + y + 2 + y=82
4y+2=82
4y= 82-2
4y=80
y=80/4
y=20
first side=2y=2(20)=40
second side=y=20
third side= 2 + y= 2 + 20 = 22
Its A trapezium
For Calculations Refer to the attachment
1/7 = 3/4x-1
3/4x=1/7+1=8/7
x=8/7*4/3=32/21