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igor_vitrenko [27]
3 years ago
10

Abu solved 231 multiplication problems. Later, he also solved 131 divison problems. How many more multiplication problems than d

ivison problems did Abu solve?
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

Easy! Abu solved 100 multiplication problems more than division problems

Step-by-step explanation: Just take 231 - 131 = 100 :D

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Rotate the triangle through 180 degrees about the origin?
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Step-by-step explanation:

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Answer:

1 term 3x²

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Step-by-step explanation:

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3 years ago
If i was born in 1983 how old would i be?
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Take the current year and subtract is from the initial year, so
This year is 2016, your are trying to find age if born in 1983
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The sum of Janos' age and David's age is 34 years. Five years ago the sum of twice Janos' age and three times David's age was 61
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8 0
3 years ago
Keep gettin this one wrong please help
Diano4ka-milaya [45]

Answer:

30 Nickels and 188 Pennies

Step-by-step explanation:

okay, so to set up the equation first, we have to assign each coin a variable, let's call them p and n:

P= number of pennies

N= number of nickels

the value of a penny is 1 cent, so 1P, and the value of a nickel is 5 cents, so 5N

The problem states that he has 218 coins, meaning that the total number of pennies and nickels adds up to 218:

P + N = 218

the total value of the coins is $3.38, so that would mean that 1P + 5N has to equal $3.38:

1P + 5N = 338

Okay, so now that we have our equations let's solve them using elimination:

we have to get a common coefficient between both equations, so let's multiply our first equation by 5:

P x 5 = 5P

N x 5 = 5N

218 x 5 = 1090

so, now we can solve by elimination:

5P + 5N = 1090

1P + 5N = 338

the N's cancel out:

4P = 752

divide both sides by 4:

P = 188

okay, so if theres a total of 218 coins, subtract 188 from 218:

218 - 188 = 30

so, there are 30 nickels and 188 pennies.

check our work:

5 x 30 = 150

1 × 188 = 188

150 + 188 = 338

338 = 338

I hope this helps! :)

5 0
4 years ago
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