Ask question

Ask question

All categories

3 years ago

13

a rock is thrown in the air from the edge of a seaside cliff. it's height in feet is represented by f(x) = - 16(×²-8x-9), where

is the numbers of seconds since the rock was thrown. the height of the rock is 0 feet when it hits water

1 answer:

Ainat [17]3 years ago

4 0

Answer:

6 seconds

Step-by-step explanation:

Just took the test :)

You might be interested in

Center -c (3,-2), radius 4.

taurus [48]

Answer:

(x-3)^2+(y+2)^2=16

Step-by-step explanation:

center (h,k) radius r

(x-h)^2+(y-k)^2=r^2

6 0

3 years ago

What is the answer to thiss

lana [24]

Hi Student!

This question is fairly simple because it gives us an equation and they also give us a value for the variable that is within the equation and they tell us evaluate the expression. So let's plug in the values and solve.

<u>Plug in the values</u>

$m^2 + 5$

$(9)^2 + 5$

<u>Factor out the exponent</u>

$(9*9) + 5$

$81 + 5$

<u>Combine</u>

$86$

Therefore, the final answer that we would get when substituting m with 9 in the given equation is that we get 86.

5 0

2 years ago

A baseball diamond is a square that is 90feet on each side. What is the distance a catcher has to throw the ball from home to se

Crank

Answer:

well, since a real baseball diamond is 90 feet on each side then the distance from homebase to second is 127 feet 3 3/8 inches

hope this helps :D

4 0

4 years ago

Read 2 more answers

Sphinxa [80]

30 because 25% minese 10

5 0

3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em /> $I \to$ <em> I-Beam</em>

<em /> $d_I \to$ <em> distance between I beam and the bridge</em>

<em /> $b \to$ <em> distance between each I beam</em>

<em />

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

<em /> $Length = 55ft\ 6in$ <em> --- length of the bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0

3 years ago