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marissa [1.9K]
3 years ago
9

Help with 13 and 14 please

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer:

I think the answer to the first question is "B"

and the second one is "D"

Step-by-step explanation:

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Step-by-step explanation:

6y/6+x/6=8/6

y+x/6=4/3

-x/6 -x/6

y=4/3-x/6

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A movie theater has a 24​-foot-high screen located 6 feet above your eye level. If you sit x feet back from the​ screen, your vi
pantera1 [17]

Answer:

The viewing angles are as follows:

For x=5 feet, θ = 0.529 radians

For x=10 feet, θ = 0.708 radians

For x=15 feet, θ = 0.726 radians

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For x=25 feet, θ = 0.640 radians

Step-by-step explanation:

The viewing angle is given as:

θ = tan⁻¹(30/x) - tan⁻¹ (6/x)

where x is the distance between you and the screen.

The question is asking us to find the viewing angle θ at various distances. The distance value needs to be substituted in the above equation in place of x. So,

<u>For x=5 feet:</u>

θ = tan⁻¹(30/5) - tan⁻¹ (6/5)

  = 1.4056 - 0.8761

θ = 0.529 radians

<u>For x = 10 feet:</u>

θ = tan⁻¹(30/10) - tan⁻¹ (6/10)

  = 1.249 - 0.540

θ = 0.708 radians

<u>For x = 15 feet:</u>

θ = tan⁻¹(30/15) - tan⁻¹ (6/15)

  = 1.107 - 0.380

θ = 0.726 radians

<u>For x = 20 feet:</u>

θ = tan⁻¹(30/20) - tan⁻¹ (6/20)

  = 0.983 - 0.291

θ = 0.691 radians

<u>For x = 25 feet:</u>

θ = tan⁻¹(30/25) - tan⁻¹ (6/25)

  = 0.876 - 0.235

θ = 0.640 radians

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2 years ago
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The constant rate is 56


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gulaghasi [49]

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