A) 1.00
Just look at where the slope crosses 2 miles and then look left on the y-axis where the price is given
1800 because the 18 cant fit in the tens
Answer:
The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.
Answer:
2.15%
Step-by-step explanation:
If you were to get the z-score for both 500 and 550 and then get the probability of both those z-scores. After getting the probability you would subtract both probability and get your answer.
Z-score:
550-400/2=3
500-400/2=2
Probability:
3 (from the Z-table) is .9987
2 (from the Z-table) is .9772
.9987-.9772= .0215
.0215 as a percentage is 2.15%