I dont understand how to find cot, sec, and csc
1 answer:
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Answer:
L (1, - 7 )
Step-by-step explanation:
give endpoints (x₁, y₁ ( and (x₂, y₂ ) then the midpoint is
( ,
)
here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )
use the midpoint formula and equate to corresponding coordinates of M
= 5 ( multiply both sides by 2 to clear the fraction )
9 + x = 10 ( subtract 9 from both sides )
x = 1
and
= - 7 ( multiply both sides by 2 )
- 7 + y = - 14 ( add 7 to both sides )
y = - 7
Then L = (1, - 7 )
The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
