Answer:
see below
Step-by-step explanation:
to hundredths : 326.63
to tenths : 326.6
to ones : 327
to tens : 330
to hundreds : 300
Answer:
B, D, E, F.
Step-by-step explanation:
In the statement, the square of an even integer is even. From the options provided, we have to select the ones that provide similar ways of expressing this.
Options B, D, E, F provided with the question and reproduced below convey the same statement in different ways:
B: Given any integer whose square is even, that integer is itself even.;
D: Any integer with an even square is even.;
E: If the square of an integer is even, then that integer is even and
F: All even integers have even squares.
To the best of my knowledge, this is what I gather the table's values mean:
"antibodies present" and "positive" give you the percent of people who had the antibodies and the tests showed they did (hence, positive).
"antibodies present" and "negative" give you the percent of people who did have the antibodies, yet the tests read otherwise (misdiagnosed, negative when it should be positive).
"antibodies not present" and "positive" also show a percentage of people who were misdiagnosed. these people did not have the antibodies yet they tested positive for them.
"antibodies not present" and "negative" show the percent of people who did not have the antibodies and who were tested to prove just that.
Step-by-step explanation:
Let's take the RHS,
we've,
<h3>(<u>Cosa</u><u>/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3><h3>(<u>Cosa/</u><u>2</u><u> </u><u>+</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3>
Let's Rationalise the Denominator.
we get,
<h3>(<u>Cosa/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3><h3><u>(</u><u>cosa</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3>
The numerator is in form of (a-b)^2 and the denominator is in form of a^2-b^2. Now,
By formula,
<h3>(<u>Cosa/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-2cosa</u><u>/</u><u>2</u><u>.</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u> </u><u>+</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u> </h3><h3> cosa</h3>
Here I substituted Cosa in place of (Cosa/2)^2 - (sina/2)^2 because it's the formula of cosa in sub multiple angle form.
<h3>In the numerator, </h3>
(sina/2)^2 + (Cosa/2)^2 =1.........( by formula)
so we have,
<h3><u>1</u><u> </u><u>-</u><u> </u><u>2</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u>.</u><u>c</u><u>o</u><u>s</u><u>a</u><u>/</u><u>2</u></h3><h3>Cosa</h3>
<h3 /><h3 /><h3><u>1</u><u> </u><u>-</u><u> </u><u>sina</u> {because 2sina/2.cosa/2=sina)</h3><h3>Cosa</h3>
LHS proved.
Thank You.