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tamaranim1 [39]
3 years ago
6

Darius has a 24-ounce sports drink he drinks 18 ounces

Mathematics
1 answer:
katovenus [111]3 years ago
6 0
Answer: 6 ounces

Explaintion: 24 minus 18 equals 6
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Hey, need help on this, What is 18.029 in expanded form?
Zigmanuir [339]

Answer:

The second one

Step-by-step explanation:

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2 years ago
What is the lcm of 3,9, and 15?
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The least common multiple that is common in all numbers but is the lowest is 3 and it's the only number that all numbers listed can be divided easily by.

Hope this helps!

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3 years ago
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Write a number of your choice, using the following clues:
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90

Step-by-step explanation:

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A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
larisa [96]

\huge \bf༆ Answer ༄

Let's solve this using unitary method ~

  • \sf3 \: seconds = 63 \:  meters

  • \sf1\: second= 63 \div 3 \:  meters

  • \sf1\: second= 21 \:  meters

  • \sf5\: seconds= 21 \times 5 \:  meters

  • \sf5\: seconds= 105 \:  meters

Therefore , the ostrich will run 105 meters in 5 seconds.

5 0
2 years ago
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