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alexgriva [62]
3 years ago
15

What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

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Using the binomial distribution, it is found that there is a 0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, for the parameters, we consider that:

  • 10% of the 9-year old children in a town have three siblings, hence p = 0.1.
  • Fifteen 9-year old children are selected at random, hence n = 15.

The probability that more than 3 of these selected children have three siblings is given by:

P(X > 3) = 1 - P(X \leq 3)

In which:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059

P(X = 1) = C_{15,1}.(0.1)^{1}.(0.9)^{14} = 0.3432

P(X = 2) = C_{15,2}.(0.1)^{2}.(0.9)^{13} = 0.2669

P(X = 3) = C_{15,3}.(0.1)^{3}.(0.9)^{12} = 0.1285

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.2059 + 0.3432 + 0.2669 + 0.1285 = 0.9445

P(X > 3) = 1 - 0.9445 = 0.0555

0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

More can be learned about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
Estimate the square root to the nearest integer and tenth square root of 8
Sever21 [200]

Answer:

√

8

≈

3

Explanation:

Note that:

2

2

=

4

<

8

<

9

=

3

2

Hence the (positive) square root of  

8

is somewhere between  

2

and  

3

. Since  

8

is much closer to  

9

=

3

2

than  

4

=

2

2

, we can deduce that the closest integer to the square root is  

3

.

We can use this proximity of the square root of  

8

to  

3

to derive an efficient method for finding approximations.

Consider a quadratic with zeros  

3

+

√

8

and  

3

−

√

8

:

(

x

−

3

−

√

8

)

(

x

−

3

+

√

8

)

=

(

x

−

3

)

2

−

8

=

x

2

−

6

x

+

1

From this quadratic, we can define a sequence of integers recursively as follows:

⎧

⎪

⎨

⎪

⎩

a

0

=

0

a

1

=

1

a

n

+

2

=

6

a

n

+

1

−

a

n

The first few terms are:

0

,

1

,

6

,

35

,

204

,

1189

,

6930

,

...

The ratio between successive terms will tend very quickly towards  

3

+

√

8

.

So:

√

8

≈

6930

1189

−

3

=

3363

1189

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2.828427

8 0
3 years ago
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Answer:


Step-by-step explanation:

8 because 2 and 2/3 times 3 equals 8/3 times 3 and the threes cancel out and there is a 8 left.

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3 years ago
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Tcecarenko [31]
2/20 is equivalent to 1/10 because 2/2 is equal to 1 and 20/2 is equal to 10.
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3 years ago
Please answer this question now
Sever21 [200]

Answer:

82 degrees

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Measure of arc DC = 360 - (145+172) = 360-317 = 43 degrees.

Measure of arc BCD = 121+43 = 164 degrees.

Measure of angle A = 164/2 = 82 degrees

8 0
3 years ago
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