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satela [25.4K]
3 years ago
12

10x+11=51 solve for x

Mathematics
2 answers:
Brut [27]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

yaroslaw [1]3 years ago
4 0
51-11= 40

10x=40

40/10

X = 4
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In △ABC, the altitudes from vertices B and C intersect at point M, so that BM = CM. Prove that △ABC is isosceles.
AlekseyPX

Answer:

m∠MBC=m∠MCB by reason base angle theorem

Step-by-step explanation:

3 0
2 years ago
What is the equation of the quadratic graph with a focus of (4,3) and a directrix of y=-6
Rufina [12.5K]

Answer:

f(x) = (1/18)x^2 - (4/9)x - 65/18

Step-by-step explanation:

Since the focus (4,3) is higher up than is the directrix y = -6, the vertex is between y = -6 and y = 3, halfway between these values, to be exact:  y = -3/2.  Thus, the y-coordinate of the vertex is (-6 + 3/2), or -4.5.  The x-coordinate of the vertex is 4, which comes from that 4 in (4,3).  Thus, the vertex is (4, -4.5) or (4, -4 1/2).

The standard equation for a vertical parabola with vertex at (h,k) is:

4p(y-k) = (x-h)^2, where p is the distance between vertex and focus or between vertex and directrix.  In this case p = 4.5.  Thus, the equation of this quadratic is 4(4.5)(y - [-4.5]) = (x - 4)^2, or

18(y+4.5) = (x-4)^2, or y+4.5 = (1/18)(x-4)^2.

Let's expand this and rewrite the result as a quadratic equation in standard form y = ax^2 + bx + c:

y + 4.5 = (1/18)(x^2 - 8x + 16).  Multiplying all terms by 18 to remove both fractions, we get:

18y + 81 = x^2 - 8x + 16.  Rearranging these terms, we get:

18y = x^2 - 8x + 16 - 81, or

18y = x^2 - 8x - 65, or

y = f(x) = (1/18)x^2 - (4/9)x - 65/18.

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Step-by-step explanation:

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Step-by-step explanation:

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