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3 years ago

Please answer now this is a big test which description best fits the group

Mathematics

1 answer:

Alina [70]3 years ago

3 0

Answer:

Always decreasing so answer B

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A model car is 8 inches long and 5.2

Sphinxa [80]

Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.

7 0

3 years ago

Need this very badly

NeTakaya

((5x5)/2)x2=50 square ft
(8x5)x2= 80 square ft
8x7= 56 square ft
50+80+56=186 square ft
D) 186 square ft

4 0

3 years ago

21x =7? A. x=3 B. None of these C. x=147 D. x=28

Varvara68 [4.7K]

Answer: B

Step-by-step explanation:

To isolate x, you divide both sides by 21

21x=7

$\frac{21x}{21}=\frac{7}{21}$

x = 7/21

Simplify by dividing both the numerator and denominator by 7

x = 1/3

Since, 1/3 is not an option, B is the correct answer

6 0

2 years ago

What is the slope of a line that is parallel to the line y = x + 2?

BigorU [14]

A slope of any line parallel to y = x + 2 will be 1.

The slope of parallel lines are always equal. Since we do not see a number next to the x in the original equation, there is an assumed 1 there. Therefore any line that is parallel with it would also have to be 1.

8 0

3 years ago

Read 2 more answers

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$

<h3>Hence the area of the shaded region is 264 cm².</h3>

5 0

2 years ago

Please answer now this is a big test which description best fits the group​

Please answer now this is a big test which description best fits the group