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Paladinen [302]
3 years ago
13

Tara has two bags of marbles. the first bag contains 6 red marbles, 5 blue marbles and 4 green marbles. the second bag contains

3 red marbles, 2 blue marbles, and 4 green marbles. tara will randomly select 1 marble from each bag. what is the probability that tara will select a blue marble from each bag.
​
Mathematics
1 answer:
Alina [70]3 years ago
7 0

Answer:

From the first bag the probability is 5 out of 15 or 1/3 simplified

The second bags probability is 4 out of 9

All the bags combined the probability is 9 out of 24

Step-by-step explanation:

The probability should be set up by putting the blue marbles as the numerator and the sum of all the marbles combined for the denominator

With everything said all you have to do is figure out the two steps an you’re good to go

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500:1000

500/500:1000/500(both divided by 500-

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4/5 expressed as a decimal as what
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To win at LOTTO in one state, one must correctly select 7 numbers from a collection of 48 numbers (1 through 48). The order in w
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See below.

Step-by-step explanation:

This is the number of permutations of 7 from 48.

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A place from this table is chosen at random. Let event A= the place is a city.
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At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
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