The best possible first step would be to multiply equation one by 4 and equation by 5 that would eliminate the y and allow you to solve for x.
In essence, 4 × (3x + 5y = 1) eq1
5 × (2x + 4y = -4) eq2
thus giving rise to 12x + 20y = 4 eq1 × 4
10x +20y = -20 eq2 × 5
You can then just subtract one equation from the other
For example, (12x + 20y = 4) - ( 10x +20y = -20 )
12x - 10x + 20y - 20y = 4 - (-20)
2x = 24
x = 12
Answer:
147 is the 24 term.
Step-by-step explanation:
Just add 6 to the number.....
3 + 6 = 9
9 + 6 = 15
next would be 21
and so on....
so, take 24 and multiply by 6
144 then add 3
147
The answer to this question is:
<span>If a quadratic equation can be factored and each factor contains only real numbers then there cannot be an imaginary solution?
</span>"True"
Hoped This Helped, <span>
Cierra725599
Your Welcome :) </span>
