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Greeley [361]
3 years ago
12

I need help overdo! I will give brainlist!

Mathematics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

1. 16 minutes

2. 65%

Step-by-step explanation:

For question 1: 20 x 0.8 = 16.

For question 2: 130000/200000 = 0.65 = 65%.

Tanya [424]3 years ago
3 0

Answer:

1. 20 (.8) = 16

It takes him 16 minutes to walk to school.  

This is because 80% as a decimal is .8 and you multiply that by how long it takes Person A to walk and you get 16.

2. 65%

Given: Full capacity=200000 litres

Amount of fuel used 130000/200000x100

Solving it, we will get 65%

Step-by-step explanation:

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NEED HELP ASAP!!!!
iren2701 [21]

Answer: 8.94

Step-by-step explanation:

By common logic, you can say that l=8, w=4 and h=2.

The diagonal of the base can be found by using Pythagorean Theorem.

Pythagorean Theorem: a²+b²=c²

Since we know the a and b of the base, we can find c, the diagonal.

a and b is the l and w. We can use the equation to find c.

8²+4²=c²

64+16=c²

80=c²

c=√80

c≈8.94

The diagonal is approximately 8.94

7 0
4 years ago
4 = t/25<br> solve for T?
scoundrel [369]
You would have to multiply 25 on both sides because it is being divided. 4 times 25 is 100.
5 0
4 years ago
Read 2 more answers
Use intercepts to graph the linear equation -1/2x+y=-4
ololo11 [35]
Do you need to switch it around or do something else?
6 0
3 years ago
Read 2 more answers
How many pounds of chamomile tea that costs $18.50 per pound must be mixed with 18 lb of orange tea that costs $12.23 per pound
Rasek [7]

Answer:

The amount of chamomile tea that has to be used in order to obtain a mixture that costs $14.32 per pound is 8.997 pounds

Step-by-step explanation:

In order to find out the amount of chamomile tea that must be used in the mixture to obtain a 14.32 $ per pound, we can use an weighted average where the price points for each kind of tea are the weights and "c" is the amount of chamomile that we have to use in order to obtain the price per pound that we want. So we have:

(18.5*c + 12.23*18)/(c + 18) = 14.32

18.5*c + 220.14 = 14.32*(c+18)

18.5*c + 220.14 = 14.32*c + 257.76

18.5*c - 14.32*c = 257.75 - 220.14

4.18*c = 37.61

c = 8.997 lb

8 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

g(y) = \frac{y-5}{y^2-3y+15}

According to the quotient rule:

d(\frac{f(y)}{h(y)})  = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}

Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10

The critical values are y = 0 and y = 10.

5 0
3 years ago
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