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kogti [31]
2 years ago
10

Please help! I’ll make you brainliest

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0

Answer:

w = 21

Step-by-step explanation:

Given that,

                      game 1                     game 2

Points               12                            18

Shots                 14                            w

One proportion is : \dfrac{12}{14}=\dfrac{6}{7}

Other proportion is : \dfrac{18}{w}

So,

\dfrac{6}{7}=\dfrac{18}{w}\\\\w=\dfrac{7\times 18}{6}\\\\w=21

So, the value of w is equal to 21.

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Annual starting salaries for college graduates is unknown. Assume that a 95% confidence interval estimate of the population mean
kumpel [21]

Answer:

A sample of 217 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

If the population standard deviation is $3,750 how large should the sample be if margin of error is $500

We have that \sigma = 3750.

We need a sample of n, and n is found when M = 500. So

M = z*\frac{\sigma}{\sqrt{n}}

500 = 1.96*\frac{3750}{\sqrt{n}}

500\sqrt{n} = 1.96*3750

\sqrt{n} = \frac{1.96*3750}{500}

(\sqrt{n})^{2} = (\frac{1.96*3750}{500})^{2}

n = 216.1

Rounding up

A sample of 217 is needed.

4 0
3 years ago
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An equation is given below.
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The first step to solving this is to collect the like terms in this equation,, which are all the numbers with an x variable attached to them.
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8 0
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Therefore your answer is Number 1)
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3 years ago
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