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lyudmila [28]
3 years ago
8

What is the area of JKL?

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0
Answer: 45.24

Explanation:

(Use the formula “1/2 a b sinC”)
Area = 1/2 x 9 x 15 x sin(51) ≈ 45.24 square units
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4 years ago
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Answer:

Proven Below

Step-by-step explanation:

If we rearrange these equations, we get that 3y = 5x + 7 and that 5y = -3x + 4. Next, to find what y equals on both equations, we divide by 3 on both sides of the first equation, where we would get that y = 5/3x + 7/3, and then divide by 5 on both sides of the second equation, where we would get that y = -3/5x + 4/5. Now, to see if two lines are perpendicular to each other, we have to see if the slopes (The number being multiplied by x. Ex.) In the equation y = 3/4x + 4, the slope is 3/4) are opposite reciprocals (If you multiply them and they are equal to -1. Ex.) 3/4 * -4/3 is equal to -1, so they are opposite reciprocals). In this case, we have -3/5 and 5/3 as slopes, and -3/5 * 5/3 is equal to -1, so they are perpendicular.

8 0
3 years ago
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faltersainse [42]

Answer:

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I need help with this ​
Margarita [4]

Answer:

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