You are running an art class and you need to buy supplies. Each student will need an easel which costs $15.49, a set of brushes
1 answer:
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Answer:
24 and 9
Step-by-step explanation:
Hi there!
Let x be equal to the larger integer.
Let y be equal to the smaller integer.
<u>1) Construct equations</u>
(The sum of two integers is 33)
(The larger is 6 more than twice the smaller)
<u>2) Solve for one of the integer</u>
Isolate x in the first equation
Plug the first equation into the second
Combine like terms
Therefore, the smaller integer is 9.
<u />
<u>3) Solve for the other integer</u>
Plug in y (9)
Therefore, the larger integer is 24.
I hope this helps!
Answer:
Draw a straight line that goes through the point (0,4) and (20,0)
Step-by-step explanation:
The y-intercept is equal to 4, since the function is already in y=mx+b form, where b is the y-intercept.
To find the x-intercept, we substitute 0 into y or in this case the f(x).
0 = -1/5 (x) + 4
1/5 x = 4
x = 20
The x-intercept is 20.
Answer:
A. see below for a graph
B. f(x, y) = f(0, 15) = 90 is the maximum point
Step-by-step explanation:
A. See below for a graph. The vertices are those defined by the second inequality, since it is completely enclosed by the first inequality: (0, 0), (0, 15), (10, 0)
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B. For f(x, y) = 4x +6y, we have ...
f(0, 0) = 0
f(0, 15) = 6·15 = 90 . . . . . the maximum point
f(10, 0) = 4·10 = 40
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<em>Comment on evaluating the objective function</em>
I find it convenient to draw the line f(x, y) = 0 on the graph and then visually choose the vertex point that will put that line as far as possible from the origin. Here, the objective function is less steep than the feasible region boundary, so vertices toward the top of the graph will maximize the objective function.
