Five Tickets To A Basketball Game Cost $60. How Much Do 2 Tickets Cost?

The dot plot shows how many swimmers are in each line at a waterpark: Dot plot titled Swimmers in Line and labeled Number of Swi

nasty-shy [4]

The answer is median, because the data is skewed and there is an outlier.

3 0

3 years ago

Read 2 more answers

Espen predicted that he would sell 32 baseball caps but he actually sold 29 baseball caps which expression would find the percen

Gre4nikov [31]

Answer:

B

Step-by-step explanation:

This is the correct answer because the difference between 32 and 29 is 3 and the intial price is 32, Hence 3/32 (100)

6 0

3 years ago

Questions are on the picture, a-e.

iris [78.8K]

The equilibrium price is $1.12.
If price is $0.98, there would be scarcity of Super Widgets.
When price is $0.98, quantity demanded is y.
When price is $0.98, quantity supplied is x.
When price is $1.22, there would be a surplus of Super Widgets.

<h3>What is equilibrium? </h3>

Equilibrium price is the price at which the quantity demanded equals the quantity supplied. The equilibrium price is $1.12.

Above equilibrium price, quantity supplied would exceed quantity demanded and there would be a surplus. When price is below equilibrium price, quantity supplied would be less quantity demanded and there would be a scarcity.

To learn more about equilibrium, please check: brainly.com/question/26075805

#SPJ1

5 0

2 years ago

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro

Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of $\pi$ , so we use the worst case scenario, which is $\pi = 0.5$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}$

$n = 1067.11$

Rounding up

A sample of 1068 is needed.

8 0

3 years ago

The data show systolic and diastolic blood pressure of certain people. Find the regression equation, letting the first variable

MakcuM [25]

Full Question:

The data show systolic and diastolic blood pressure of certain people. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted diastolic pressure for a person with a systolic reading of 113. use a significance level of 0.05.

Systolic| 150 129 142 112 134 122 126 120

Diastolic| 88 96 106 80 98 63 95 64

a. What is the regression equation?

^y = __ + __x (Round to two decimal places as needed.)

b. What is the best predicted value?

^y is about __ (Round to one decimal place as needed.)

Answer:

A. yhat = a + bx = -10.64 + 0.75x

B. 74.0

Step-by-step explanation:

A. To find the regression equation here, we apply the formulas and then apply it to find the value of y given value of x:

calculate xbar and ybar which is the average of the variables:

Where n(number of values in x or y)=8

xbar = sum of x/n = 129.375

ybar = sum of y/n = 86.25

to calculate b

b= [Sum x^2 * Sum y - Sum x * Sum x*y] / [N*Sum x^2 - (Sum x)^2]

b = 0.74891

To calculate a

a = ybar - b * xbar = -10.64023

Regression equation:

y=mx+b= -10.64 + 0.75x

B. given x = 113,

y = -10.64023 + 0.74891 * 113

y= 74.0

5 0

3 years ago