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cluponka [151]
3 years ago
8

Please helps?!?!?!?!?!?!?!?!?!

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:

47x^3\sqrt{5x}

Step-by-step explanation:

The objective is to combine the terms to make one radical, so therefore we know that we will have to take a \sqrt{5} out of the second radical \sqrt{180}.

If we divide 180 by 5, we will get 36, so now we have

\sqrt{180}=\sqrt{5}×\sqrt{36}

\sqrt{36} can be simplied into just 6.

So now the expression becomes

-\sqrt{5x^7}+8x^2*6 \sqrt{5x^3}

Then we can further simplify by moving the x^{2} into the radical to get two common terms with \sqrt{5x^7}.

x^{2} =\sqrt{x^4}, so we now have

-\sqrt{5x^7}+ 8\sqrt{x^4} *6 \sqrt{5x^3}

So then we can combine the two radicals to get the expression to

-\sqrt{5x^7}+48\sqrt{5x^7}

We now see that we have two terms with a common radical, and coefficients of -1, and 48.

That allows us to simplify further to

47\sqrt{5x^7}

Here, we can take out \sqrt{x^6}, which is x^3, and get the final simplied form to be

47x^3\sqrt{5x}

Hope this helped.

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sweet [91]

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I. Volume = 301.6 cm³ (to 1d.p)

II. CSA = 188.5 cm² (to 1d.p)

Step-by-step explanation:

<u>Given the following data;</u>

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Radius, r = 6cm

Curved length = 10cm

a. To find the volume of the cone

V = \frac{1}{3} \pi r^{2}h

Where;

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  • r is the radius of the base of the cone.
  • h is the height of the cone.

Substituting into the equation, we have;

Volume = \frac{1}{3} * 3.142*6^{2}*8

Volume = \frac{1}{3} * 3.142*36*8

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<em>Volume = 301.6 cm³</em><em> </em>(to 1d.p)

b. The curved surface area of the cone

CSA = \pi rl

Where;

  • CSA is the curved surface area of the cone.
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Substituting into the equation, we have;

CSA = 3.142*6*10

<em>CSA = 188.5 cm²</em> (to 1d.p)

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3.5 - 1.6 = 1.9

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