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Black_prince [1.1K]
3 years ago
9

3. International basketball competitions are played on a rectangular court where the length is 2x-2 and the width is x. If the p

erimeter of the court is 86 m. what are the dimensions of the court?
Mathematics
2 answers:
Daniel [21]3 years ago
7 0

Answer:

length is 28m and width is 15m

Step-by-step explanation:

Let length = l

and width = b

According to the given condition,

l = 2b -2

Now,

Perimeter of a rectangle, P = 2(l+b)

According to question

P = 86

2(l+b) = 86

l + b = 43

2b -2 + b = 43

3b = 45

b =15

Therefore, l = 2x15 -2 = 28

So length is 28m and width is 15m

Mandarinka [93]3 years ago
3 0

Answer:

  • 28 m and 15 m

Step-by-step explanation:

<u>Perimeter formula is:</u>

  • P = 2(l + w)

<u>Given:</u>

  • l = 2x - 2 and w = x
  • P = 86 m

<u>Substitute and solve for x:</u>

  • 2(2x - 2 + x) = 86
  • 3x - 2 = 43
  • 3x = 45
  • x = 15

<u>Then find the values of l and w:</u>

  • l = 2*15 - 2 = 28 m
  • w = 15 m
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